Is there a modular integer division operator? I tried 5 % 3 and it doesn’t work. I can’t find the function in Math.Int.
Since you are using the exact same numbers from the overview in the docs, I suppose you don’t want to use mod(5, 3) but are looking for a infix operator, which does not exist (yet)?
Total coincidence on using the same numbers.
Must have been a case of “great minds think alike” then. 
2 Likes
3 and 5 might be inspired by FizzBuzz 
1 Like